1/36=6^2x-4

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Solution for 1/36=6^2x-4 equation:



1/36=6^2x-4
We move all terms to the left:
1/36-(6^2x-4)=0
We get rid of parentheses
-6^2x+4+1/36=0
We multiply all the terms by the denominator
-6^2x*36+1+4*36=0
We add all the numbers together, and all the variables
-6^2x*36+145=0
Wy multiply elements
-216x^2+145=0
a = -216; b = 0; c = +145;
Δ = b2-4ac
Δ = 02-4·(-216)·145
Δ = 125280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{125280}=\sqrt{144*870}=\sqrt{144}*\sqrt{870}=12\sqrt{870}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{870}}{2*-216}=\frac{0-12\sqrt{870}}{-432} =-\frac{12\sqrt{870}}{-432} =-\frac{\sqrt{870}}{-36} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{870}}{2*-216}=\frac{0+12\sqrt{870}}{-432} =\frac{12\sqrt{870}}{-432} =\frac{\sqrt{870}}{-36} $

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